A. Stones on the Table
time limit per test2 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard outputThere are n stones on the table in a row, each of them can be re
There are n stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them.
The first line contains integer n (1 ≤ n ≤ 50) — the number of stones on the table.
The next line contains string s, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to n from left to right. Then the i-th character s equals "R", if the i-th stone is red, "G", if it's green and "B", if it's blue.
Print a single integer — the answer to the problem.
3 RRG
1
5 RRRRR
4
4 BRBG
0
解题说明:顺序遍历即可,贪心,不是DP
#include <iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
using namespace std;
int main()
{
int i,n,j;
int sum;
char a[101];
sum=0;
scanf("%d",&n);
scanf("%s",&a);
j=0;
for(i=1;i<n;i++)
{
if(a[i]==a[j])
{
sum++;
}
else
{
j=i;
}
}
printf("%d\n",sum);
return 0;
}
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